Question

When a slice of buttered toast is accidentally pushed over the edge of a counter, it rotates

as it falls. If the distance to the floor is 80cm and for rotation less than 1 rev, what are the

(i) smallest and (ii) largest angular speeds that cause the toast to hit and then topple to be
butter side down?




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Answer 1

Answer:

the largest angle (less than 1 revolution) turned for the toast to land butter-side down is Δθmax=0.75rev=3π/2rad. This corresponds to an angular speed of

ωmax=ΔθmaxΔt=π/2rad0.4s=15π4rad/s.

Explanation:

mallest angular speed is 5π4rad/s and largest angular speed is 15π4rads.

smallest angular speed is π4rad/s and largest angular speed is 3π4rad/s

smallest angular speed is π2rad/s and largest angular speed is 3π2rad/s.

smallest angular speed is 5π2rad/s and largest angular speed is 15π2rad/s.

Answer :

A

Solution :

(a) The time it takes for the buttered toast to hit floor is.

Δt=2hg−−−√=2(8m)10m/s2−−−−−−−√=0.40s

The smallest angle turned for the toast to land butter - side down is Delatθmin=14rev=π/2. This corresponds to an angular speed of

ωmin=ΔθminΔt=π/2rad0.4s=5π4rad/s

The largest angle (less than 1 revolution) turned for the toast to land butter-side down is Δθmax=0.75rev=3π/2rad. This corresponds to an angular speed of

ωmax=ΔθmaxΔt=π/2rad0.4s=15π4rad/s.

Answer 2

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