Question

When a sound of frequency 300 words passes through mediam the maximum displacement of a particle of the?

Answer 1

λ2=0.1 cm⇒λ=0.2 cm
Maximum velocity of the particle,
vmax=νλ=300×0.2×π cm/s=60π cm/s

Answer 2

solve :- frequency of sound wave = 300Hz

amplitude of a particle of the medium = 0.1 cm

we know, formula of maximum velocity = angular frequency × amplitude

angular frequency = 2π × frequency

= 2π × 300 rad/s

= 600π rad/s

now, maximum velocity of wave = 600π rad/s × 0.1cm

= 600π × 0.1/100 m/s

= 0.6π m/s