Question

When a sound wave of frequency 300 Hz passes through a medium, the maximum displacement of a particle of the medium is 0.1 cm. The maximum velocity of the particle is equal to ........... (a) 60π cm/s (b) 30π cm/s (c) 30 cm/s (d) 60 cm/s

Answer 1

Answer:

b) is the answer of this question

Answer 2

Answer:

(a) 60π cm/s

Explanation:

As per the question,

Given data:

Maximum displacement of particle = A = Amplitude = 0.1 cm

Frequency of a sound wave = n = 300 Hz

As we know the formula for maximum velocity is

$V_{max} = A \cdot \omega$

Where,

A = amplitude

ω = angular velocity  = 2π × n

where n = frequency

Therefore,

$V_{max} = 0.1 \times 2\pi \times 300$

$V_{max} = 60 \pi$

Hence, the maximum velocity of the particle is equal to = 60π cm/s.

Hence, the correct option is (a).