Question

when a spring is compressed by 3 cm its pe is u.when compressed by 6 cm its p.e will be​

Answer 1

Answer:

Potential energy stored in a compressed or expanded spring is given by

$U = \frac{1}{2}kx^2$

where 'x' is the amount of compression or elongation of the spring from its relaxed state

∵ U ∝ x²

if the length doubles

U₂ ∝ (2x)² ⇒ U₂ ∝ 4x² ⇒ U₂ = 4U

its final PE = 4U