Question

when a stone is in the air what is it is 4n what is the weight of the stone in the water ​

Answer 1

Weight difference =

150-100 = 50 N = Buoyant force of water

Buoyant Force in water(Fb) = density of water x g x volume of body(Vb)

50 = 1000 x 9.81 x Vb

Vb = 50/9810 cubic meter

Now, in air

Weight of body = mg = 150 N

Mass of body,m = 150/9.81 Kg

So,

Density of body = m/ Vb

= 150/9.81 ÷ 50/9810

= 3000 kg per cubic meter

Specific gravity of body = density of body ÷ density of water

= 3000 ÷ 1000

Specific gravity of body = 3.

I hope you are understand my solution

Answer 2

Answer:

The weight of stone in air = 18 N

Step-by-step explanation:

Given,

Weight in water(W_w) = 14 N

Displaced water = 4 N

∴Weight in air can be determined as :

Weight in air(W_a) = Weight in water(W_w) + water displaces

W_a = 14 N + 4 N

∴ Weight in air(W_a) = 18 N

Explanation:

hope it helps u

mark as brainliest

follow me.....