Question

When a stone of 200gwt is completely immersed in water, 60gwt of water is displaced. What is the weight of the stone in water?

Answer 1

Answer:If 120 ml of water is displaced means, volume of stone is 120 ml.

 

weight of stone in water = volume×(ρs - ρw)g = 120×(ρs - ρw)g  gram.

 

where ρs is density of stone, ρw  is density of water.

mass of the stone and density of stone will remain same everywhere, they will not change when stone is inside water.

Explanation:

Answer 2

Given:

When a stone of 200gwt is completely immersed in water, 60gwt of water is displaced.

To find:

Weight of stone in water.

Calculation:

Archimedes Principle states that whenever an object is immersed in a fluid and displaces a certain weight of fluid, it will experience the same magnitude of upward buoyant force.

So, in this case buoyant force is 60 gwt.

So, net weight of stone in water is :

$\therefore \: \sf{w_{water} = w_{air} - (buoyant \: f)}$

$= > \: \sf{w_{water} = 120- 60}$

$= > \: \sf{w_{water} = 60 \: gwt}$

So, weight of stone in water is 60 gwt.