when a stone of mass 200g is completely immersed in a beaker carrying full of water 50g of water overflow
a. what will be the weight of stone in water
b. if the stones were immersed in kerosene instead of water what will be the change in volume of overflow and kerosene
c. what about the weight of our fluid kerosene
Answers
Answer:
Wt of stone in water=200-50=150g
Since density of water is 1, volume of water displaced =50cc.
When stone is immersed in kerosene, the same amount 50 cc will be displaced.
Given: a stone of mass 200g is completely immersed in a beaker carrying full of water, 50g of water overflow
To find: a. what will be the weight of the stone in water
b. if the stones were immersed in kerosene instead of water what will be the change in volume of overflow and kerosene
c. what about the weight of our fluid kerosene
Solution: According to Archimedes principle, whenever any object is immersed in some fluid, it will displace some amount of fluid, it will experience the same amount of upward force that is buoyancy force.
here in this question buoyancy force will be 50g.
writing equation according to Archimedes principle as
Wwater= Wair- buoyant force
Wwater = 200-50
Wwater = 150g
a) therefore, the weight of the stone in water will be 150g.
a) therefore, the weight of the stone in water will be 150g.b) even if the stone is immersed in kerosene, an equal amount of fluid will be overflowed on immersion.
a) therefore, the weight of the stone in water will be 150g.
b) even if the stone is immersed in kerosene, an equal amount of fluid will be overflowed on immersion.
c) as the density of kerosene is less, therefore, we can say that mass of the kerosene overflowed will be less than that of water.