When a substance having mass 3 kg
receives 600 cal of heat, its temperature
increases by 10'C. What is the specific
heat of the substance?
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6
Answer:
20 J/kg.c
Explanation:
mass.3 kg
change in temperature.10 c
heat.600kcal
- specific heat= 600÷3×10
= 20 J/kg.c
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