when a substance having Mass 3 kg receives 600 calorie of heat its temperature increases by 10 degree Celsius what is specific heat of the substance
Answers
Answered by
28
we know that Q=msdt
Q is 600 calori
M is 3 kg
dt is 10 degree
600cal=3×10×s×kgcelsius
s=20. Cal/kg celsius
Q is 600 calori
M is 3 kg
dt is 10 degree
600cal=3×10×s×kgcelsius
s=20. Cal/kg celsius
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Answered by
9
the correct answer is .02 cal per gmc
Not correct this ANS
ya the ans in tb is 0.00033 but its wrong
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