When a system is taken from state i to state f along the path iaf , it is found that Q = 50cal and W = 20cal .Along the path ibf , Q = 36cal. W along the path ibf is [AIEEE 2007]
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Answered by
0
Answer:
By first law of thermodynamics :
Q=ΔU+W
In path iaf:
50=ΔU+20
∴ΔU=30
As this change in internal energy is between i & f and does not depend on path.
Therefore along path ibf:
Q=ΔU+W
36=30+W
∴W=6 cal
Answered by
1
Answer:
By first law of thermodynamics :
Q=ΔU+W
In path iaf:
50=ΔU+20
∴ΔU=30
As this change in internal energy is between i & f and does not depend on path.
Therefore along path ibf:
Q=ΔU+W
36=30+W
∴W=6 cal
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