Question

When a thin plate of refractive

index 1.5 is placed in the path of one of interfering beams of Michaelson Interferometer,a shift of 30 fringes is observed. If the thickness of plate is 0.018mm, the wavelength of the used light is​

Answer 1

12 is the

correct answer

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Answer 2

Given:

Refractive index of plate = 1.5

Number of fringes observed = 30

thickness of plate = 0,018mm

To find:

The wavelength of the light used.

Solution:

The device used here is Michael Interferometer which is a device that breaks down a light beam into fringes and recombines them after they have traveled different optical paths.

The formula that we obtain from this experiment is for calculating the number of fringes when we know the value of the wavelength of the light used, distance, and refractive index of the material.

fringes = $\frac{2(distance)}{wavelength}(n-1)$

we will put the values of fringes, refractive index, and distance to obtain the wavelength of light used.

33 = $\frac{2(0.000018)}{wavelength} (1.5-1)$

wavelength = 303.03 nm.

Therefore, the wavelength of light used is 303.03 nm.