Question

When a thin transparent plate of thickness t and refractive index is placed in the path of one of the two interfering waves of light then the path difference changes b?

Answer 1

Answer:

Path difference is $t(\mu -1)$

Explanation:

let thickness of the transparent plate to be $t$

Optical path of wave is $\mu t$

where $\mu$ is the refractive index

then the path difference changes is

=$\mu t-t\\=t(\mu -1)$

Answer 2

The path difference changes is $t(\mu-1)$.

Explanation:

Given that,

Thickness = t

Refractive index = μ

The optical path difference arises only for the part of thickness t because the light travels different distance in different medium.

The thickness of the transparent plate is t

.

The optical path of wave is μt,

We need  to calculate the path difference changes

Using formula of path difference

$\Delta x = x_{2}-x_{1}$

Put the value into the formula

$\Delta x =\mu t-t$

$\Delta x=t(\mu-1)$

Hence, The path difference changes is $t(\mu-1)$.

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Topic : path difference

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