When a tuning fork A f unknown frequency is sounded with another tuning fork B of frequency 256 Hz, 3 beats per second are observed. After that A is loaded with wax and sounded, the beat frequency decreases. Find the frequency of the tuning fork A.
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Thus the frequency of tuning fork A will be 259 Hz.
Explanation:
We are given that:
- Let unknown frequency be = A
- Known frequency "B" = 256 Hz
- Number of beats produced "x" = 3
Solution:
Now the difference between nA and nB
nA - nB = x
By changing the sequence
nB - nA = x which is wrong
Now
nA = nB + x = 256 + 3 = 259 Hz
Thus the frequency of tuning fork A will be 259 Hz
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