Question

when a two digit number is divided by the sum of its digit the quotient is 8 if the tens digit is diminished by three times the units digit the remainder is 1 what is the number​

Answer 1

I can't understand the question

Answer 2

Answer:

72

Step-by-step explanation:

Let’s consider the digit at tens place as x

And let the digit at unit place be y

The number is 10 × x + y × 1 = 10x + y

Then according to the first condition, we have

(10x + y)/ (x + y) = 8

10x + y = 8 (x + y)

10x + y = 8x + 8y

10x – 8x + y – 8y = 0

2x – 7y = 0 … (i)

And according to the second condition, we have

x – 3y = 1 … (ii)

Performing (i) – 2 x (ii), we get

2x – 7y = 0

2x – 6y = 2

(-)—(+)—(-)

-y = -2

y = 2

Substituting the value of y in (i), we get

2x – 7(2) = 0

2x = 14

x = 14/2

x = 7

Therefore, the number is = 10 x 7 + 2 = 70 + 2 = 72.