Math, asked by ANIZZZZ, 6 months ago

When a two digit number is divided by the sum of its
digits, the quotient is 7. If the ten's digit is diminished
by twice the unit's digit, the remainder is zero. What
is the number?​

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Answers

Answered by MysteriousAryan
0

Answer:

When a two digit number is divided by the sum of its digit, the quotient is 4. If the digit are interchanged, the reversed number is 6 less than twice the original number. What is the number?

.

Let the digit at tens place be x and the digit at units place be y.

Therefore the no. is— (10x+y ) ——————————-as x is at tens place.

(10x+y)/(x+y) =4

10x+y=4(x+y)

10x+y=4x+4y

6x=3y

(2x=y )——————————————————————————————- 1

Now the digits are interchanged.

Therefore the new no is —( 10y+x)

As the new no is 6 less than twice the original no.—

Therefore,

10y+x=2(10x+y)-6

10y+x+6=20x+2y

10y-2y+6=20x-x

8y+6=19x

(8y+6)/19=x

As we have got the value of x,lets substitute it in equation 1

Therefore,

2(8y+6)/19=y

16y+12=19y

12=19y-16y

12=3y

y=12/3=4

y=4

Substituting the value of y in equation 1

Therefore,

2x=4

x=4/2=2

x=2

y=4

Therefore the no. is

10x+y=10(2)+4=20+4=24

Therefore the no. is 24

Answered by Anonymous
1

13

please mark to brainlist

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