Question

when a two digit number is divided by the sum of its digits the quotient is 8 . If the ten's digit is diminished by three times the unit's digit, the remainder is 1. What is the number?

Answer 1

hii mate!!

Let the tens digit be x
Let the units digit be y

The required number is 10x+y

The sum of the digits is x+y

Given, (10x+y)/(x+y) = 8
=> 10x+y = 8(x+y)
=> 10x+y = 8x+8y
=> 10x-8x = 8y-y
=> 2x = 7y
=> 2x-7y = 0 ------------(1)

Given, x-3y = 1
=> 2x-6y=2 -------------(2)

Solving (1) and (2), we get x=7 and y=2

The answer is 72

hope it helps !!☺☺

Answer 2

This is my answer hope this helpfull for everyone.