When a two digit number is multiplied by 9 , it becomes 2 time of the number that is obtained by interchanging the digits. If the difference of the digit is 7. find the number.....
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Let the tens place digit be a
And unit place digit be b
According to first condition,
b - a = 7 -------(1)
According to second condition,
9 (10a + b) = 2 ( 10b + a)
=> 90a + 9b = 20b + 2a
=> 88a = 11b
=> b = 8a
On substituting the value of b in equation 1, we get
8a - a = 7
=> 7a = 7
=> a = 1
b = 8 × 1
=> b = 8
Required number = 18
And unit place digit be b
According to first condition,
b - a = 7 -------(1)
According to second condition,
9 (10a + b) = 2 ( 10b + a)
=> 90a + 9b = 20b + 2a
=> 88a = 11b
=> b = 8a
On substituting the value of b in equation 1, we get
8a - a = 7
=> 7a = 7
=> a = 1
b = 8 × 1
=> b = 8
Required number = 18
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