Question

when a two digit number is reversed, the number so formed is 63 more than X. if the sum of digits of X is 11 then what is the value of x +21?​

Answer 1

The number is 29 and the reversed number is 92.

X + 21 = 23

Step-by-step explanation:

Given: When a two digit number is reversed, the number so formed is 63 more than X.  

Sum of digits of X is 11

Find: x +21

Let x be the tens place and y be the ones place of the given number.

The number will be 10x + y.

Reversed number will be x + 10y.

So (x + 10y) - (10x + y) =  63

-9x + 9y = 63  

x - y = -7-----------------------(1)

x + y = 11-----------------------(2)

Adding 1 & 2, we get 2x = 4

So x = 2

substituting in (2), we get 2 + y = 11

So y = 9

X+ 21 = 2 + 21 = 23

The number is 29 and the reversed number is 92.