when a two digits number is divided by the sum of its digits , then the quotient is 8 and the remainder is 2 . If the digits are reversed and the resulting number so formed is divided by the sum of the digits , the quotient is 2 and the reamaider is 2 and the remainder is 8. Find the two digits number.
Answers
AnswEr:-
Two digits number = 82
Let the digit at unit's place be m & digit at ten's place be n
∴ Two digits number = m + 10n
Case 1:-
• Two digits number is divided by sum of digits, quotient is 8 & remainder is 2
As we know remainder formula:-
☛ Dividend = Quotient × Divisor + Remainder
Here, dividend = Two digits number & divisor = Sum of digits
⇒ m + 10n = 8 × (m + n) + 2
⇒ m + 10n = 8m + 8n + 2
⇒ m - 8m + 10n - 8n = 2
⇒ 2n - 7m = 2
⇒ 2n = 7m + 2
⇒ n = (7m + 2)/2 - - - (Eq.1)
Case 2:-
• Digits interchanged, two digits number is divided by sum of digits, quotient is 2 & remainder is 8.
Now, when digits interchanged:-
⇒ Two digits number = 10m + n
Using same formula we get:-
⇒ 10m + n = 2 × (m + n) + 8
⇒ 10m + n = 2m + 2n + 8
⇒ 10m - 2m + n - 2n = 8
⇒ 8m - n = 8
⇒ 8m = n + 8
⇒ n = 8m - 8 - - - (Eq.2)
Comparing both equations:-
⇒ (7m + 2)/2 = 8m - 8
⇒ 7m + 2 = 2(8m - 8)
⇒ 7m + 2 = 16m - 16
⇒ 7m - 16m = -16 - 2
⇒ -9m = -18
⇒ m = -18/-9
⇒ m = 2
So, digit at unit's place = 2
Put this value in (Eq.2)
⇒ n = 8(2) - 8
⇒ n = 16 - 8
⇒ n = 8
So, digit at ten's place = 8
Now two digit number:-
⇒ Two digit number = 2 + 10(8)
⇒ Two digit number = 2 + 80
⇒ Two digit number = 82
Therefore,
Two digit number = 82 .
Answer:
72
Step-by-step explanation:
Let the ten digits be x and let the units digits be y
Then, the required number is 10x+y
According to the question sum of digits =x+y
x+y
10x+y
=8
⇒10x+y=8x+8y
⇒10x−8y=8y−y
⇒2x=7y
⇒2x−7y=0−−−−−−−−−−(1)
Given,
x−3y=1−−−−−−−−−−−−−(2)
from equation (1) and (2)
2x−7y=0
(x−3y=1)×2
2x−7y=0
2x−6y=2
− + −
−−−−−−−−
−y=−2
y=2
put in equation (1)
2x−7y=0
2x−×2=0
2x=14
x=7
Hence the number is 10x+y
⇒ 10×7+2
=72
Hence, this is the answer.