When a uniform rod is heated, which of the follwing quantity of the rod will increase
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Answer:
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Explanation:
The moment of inertia of a rod about a perpendicular bisector is ML^2 / 12.
Change in M.I. is d(ML^2 / 12) = ML dL / 6
dL = aL dt
dI = aL dt ML / 6 = 2a(ML^2/12) dt = 2aIdt
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Answered by
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Answer:
heyy..........
Moment of inertia increases.
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