When a vander waal's gas undergoes free expansion then its temperature (a) Decreases (b) Increases (c) Does not change (d) Depends upon the nature of the gas
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depends upon the nature of the gas
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Its temperature decreases.
Free expansion of any ideal gas shows dT= 0, dU= 0, where T and U are temperature and internal energy respectively.
But in case of a real gas or VDW gas, when it expands, it loses heat, therefore its temperature decreases.
Maybe if we use the real gas equation, this will be easier to understand.
As the gas expands, volume increases.
(P + an²/ V²) (V-nb) = nRT
From the equation, clearly, temperature decreases.
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