Question

when a voltage drop across
a ph junction diode is increased from 0.70 v to 0.71 v the change in the diodw current is 10 mA what is the dynamic resistance of diode​

Answer 1

Answer:

See below.

Explanation:

For a p-n junction diode, the dynamic resistance is given by,

$r=\dfrac{\Delta V}{\Delta i}$

We are given,

$\begin{aligned}\Delta V=0.71-0.70\\ =0.01 \ V\end{aligned}$

and,

$\begin{aligned}\Delta i=10\times 10^{-3}A\\ =10^{-2}A\end{aligned}$

Substituting the values,

$r=\dfrac{10^{-2}}{10^{-2}}=1\Omega$