Question

When a voltage of 120 V is applied to a coil A, the current taken is 8 A and the power is 120 W. When the same voltage is applied to a coil B, the current is 10 A and the power is 500 W. What current and power will be taken when 120 V is applied to the above two coils connected in series?​

Answer 1

Answer:

Z1 = 100/8 = 12.5 Ω ; P = I2 . R1 or 120 = 82 × R1 ; R1 = 15/8 ΩX1 = √(Z21 - R21) = √(12.52 - (15/8)2) = 12.36ΩZ2 = 100/10 = 10 Ω ; 500 = 102 × R2 or R2 = 5 ΩX2 = √(102 - 52) = 8.66ΩWith Joined in Series R = R1 + R2 = (15/8) + 5 = 55/9 Ω; X = 12.36 + 8.66 = 21.02 ΩZ = √((55/8)2 + (21.02)2) =Ω I = 100/22.1 = 4.52 A, P = I2R = 4.522 × 55/8 = 140W

Explanation:

Hope this helps you

Answer 2

Answer:

• 3A we have to take it matmintain equal voltage