When a voltage V = Vo cos wt is applied across
a resistor of resistance R, the average power
dissipated per cycle in the resistor is given by
(1) Vo / V2R
(2)Vo / root 2 omega R
(3)Vo^2 /2R
(4)Vo^ / 2 omega R
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Answer:
the resistance is vo / v2r
Explanation:
W=
F
⋅
r
=
F
⋅(
r
2
−
r
1
)
⇒W=(
i
^
+2
j
^
+3
k
^
)⋅((
i
^
−
j
^
+2
k
^
)−(
i
^
+
j
^
+
k
^
))
⇒W=(
i
^
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