when a wire elongates along the length it's radius is
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Answer:
Young Modulus ⇒4=
A
0
△L
FL
0
△L=F×L
0
/A
0
4
A
0
=πr
0
2
F=mg=9×98=88.2 N
△L=9mm=0.009 m
A=π(2r)
2
=4A
0
elongation will be : DL
′
=
AY
F×L
0
=
4A
0
Y
F×L
0
△L
′
=
4
△L
=
4
9
∴△L
′
=2.25 mm
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