when /AB/ √90 , find the value of m which points are (3,6) (7,m)
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Explanation:
The points are colliner if the area of triangle is 0.
0=
2
1
∣3(6−
2
15
)+m(
2
15
−5)+
2
1
(5−6)∣
0=3(
2
−3
)+m(
2
5
)−
2
1
0=−9+5m−1
10=5m⇒m=2
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