Question

When abody moving in circular path of tadius 7 cm what is distance when it complete one revolution

Answer 1

Answer:

44 cm

Explanation:

Distance covered in one complete revolution

of the circular path = Circumference of the circular path.

$= 2\pi.r$

$= 2 \times \frac{22}{7} \times 7 \: cm$

$= 2 \times 22 \: cm$

$= 44 \: cm$