Question

when aeroplane lands at 1 6 km per hour and stops after covering the remedy of 2 kilometre calculate acceleration and time in which it comes to rest

Answer 1

V² -U² = 2as
-256 = 2x2xa
64 = a
V = u + at
0 = 16 + 64xt
T = 1/4 seconds

Answer 2

here v =0
we know v^2-u^2=2as
=>A =u^2/2s
=>a=16^2/2.2=64m/s^2
time =velocity /acceleration =16/64=1/4sec
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