Question

when AGlgNo3 was treated with 5.08 gram of a sample of iron chloride 11.48 gram gram of agcl was formed 6.51 of another iron chloride gave 17.22 gram of agcl on treatment with AgNo3 so what agreement with law of multiple proportion​

Answer 1

Answer:

For 1st case, xAgNO3 + FeClx→ x AgCl 1 mol of FeClx gives x moles of AgCl . 5.0856 + 35.5x mol gives 5.0856 + 35.5x moles AgCl 5.0856 + 35.5x = 11.48143.5