Question

When AgNO3​ was treated with 5.08g of a sample iron chloride, 11.48g pf AgCL was formed 6.51 of another iron chloride gave 17.22g of AgCI on treatment with AgNO3​. Show that these results illustrate the law of multiplle proportions.

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Answer 1

Answer:

For 1st case, xAgNO 3  +FeClx  →xAgCl

1 mol of FeCl  x  gives x moles of AgCl.

∴5.08 /  56+35.5x  mol gives   5.08 /  56+35.5x  molesAgCl

5.08 /  56+35.5x= 11.48 /143.5  

⇒x=2

For 2nd case, yAgNO3  +FeCly  →yAgCl

1 mol of FeCl y  gives y moles AgCl

∴ ∴6.51  /  56+35.5x  mol gives   6.51  /  56+35.5x  molesAgCl

6.51  /  56+35.5x= 17.22 /143.5   ​

⇒y≈3

 

x/y=2/3

→ This is in accordance with law of proportions.