Question

when an 8-bit serial out shift out shift register is used with a clock frequency of 15 MHz . what is the time delay between the serial input and the q3 output​

Answer 1

Answer:

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Answer 2

Given:

Clock frequency = 15 MHz = 15 × 10⁶ Hz

To find:

What is the time delay between the serial input and the Q₃ output​?

Solution:

One bit of data is shifted at a time in serial shifting.

From Q₀ to Q₃, total number of bits that are shifted is 4bit

Therefore, 4 / 15 × 10⁶ s = 0.267 × 10⁻⁶ s = 267 × 10⁻⁹ s = 267 ns

Therefore, the time delay between the serial input and the Q₃ output​ is 267 ns.