When an a-particle of mass ‘m' moving with velocity v
bombards on a heavy nucleus of charge Ze, its distance
of closest approach from the nucleus depends on m as :
Also say why The formula is taken as Ze²/r0.
The formula what we know is 1/4π€0 x Ze²/r².
Why we are taking r² as r0?
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Answer:
r square here, shows distance of closest approach
Explanation:
Here, this distance is rO.
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