Physics, asked by Mikeey, 10 months ago

when an air bubble of radius r is at depth h below the free surface of liquid of density ρ and surface tension is 'S'. the excess pressure inside the bubble is??

Answers

Answered by harsharora111
0

Answer:

Pex = 2S /r + pgh

it has only one free surface

inside

Thanks for Reading

Answered by Anonymous
0

It has no component perpendicular to the horizontal surface. As a result, there is no pressure difference between the liquid side and the vapour side. ... Thus, there is always an excess of pressure on the concave side of a curved liquid surface over the pressure on its convex side due to surface tension.

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