When an air bubble of radius r rises from the bottom to the surface of the water lake its radius becomes 5r/4. If the
temperature is constant and atmospheric pressure is 10 m of water column, the depth of the lake is approximately
(A)
3.3 m
(B)
5.3 m
(C)
9.53 m
(D)
6.5 m
Answers
Answered by
0
Answer:
Approximately=5.3meter will your answer , otherwise ask to google to get the answer....
Answered by
1
Answer:9.5 m
Explanation:
Pressure at bottom
(P
1
)=P
atm
+ρgh+
R
1
4T
__________(1)
Pressure at top
(P
2
)=P
atm
+
R
2
4T
____________(2)
Given R
1
=r
R
2
=
4
5r
So P
1
V
1
=P
2
V
2
(P
1
)
3
4
πr
3
=(P
2
)
3
4
64
125r
3
Dividing (1) and (2)
P
2
P
1
=
P
atm
+
5r
4T×4
P
atm
+ρgh+
r
4T
=
64
125
ρg(10)
ρg(10)+ρgh
=
64
125
640+64h=1250
On solving we get h = 9.5 m
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