Question

When an air bubble of radius r rises from the bottom to the surface of a lake, its radius becomes taking the atmospheric pressure to be equal to 10 m height of water column, the depth of the lake would approximately be : (ignore the surface tension and the effect of temperature)?

Answer 1

Formula:

P1*V1 = P2V2

P1 is pressure at the bottom equals to (10+h) g due to column of lake

P2 is pressure at the top equals to 10g

V1 is equals to 4/3πr^3

V2 is equals to 4/3π(2r^3)

Putting the values the depth is 70m provided that temperature is constant.