Question

When an alpha particle is accelerated by a P.D. of 3 volt, its energy is :

Answer 1

Charge on alpha particles= 2 units of electronic charge =2×4.8×10^-10 esu of charge = 9.6×10^-10 esu of charge

Accelerating voltage= V volts= V/300 esu of potential

Energy E gained by the alpha particle in being accelerated by the applied potential difference= charge ( in esu) × potential difference in esu = 9.6×10^-10×V/300 = 3.2×10^-12 V ergs = 3.2 × (10)<-12 ×3 ergs
= 9.6×(10)<-12 ergs.


hope it will help you..