Question

When an antacid tablet is used, calcium hydroxide interacts with hydrochloric acid in the stomach to form inert calcium chloride CaCl2 and water. If the molar mass of Ca(OH)2 75 grams/mol, how many mols of HCl are required to fully react with 150 g of Ca(OH)2?

Answer 1

Answer:

NUMBER OF MOLES of HCl ; Molarity of solution x Volume of Solution

# of moles of HCl = (0.40 mol/L ) x 350 mL

= (0.40 mol/L ) x 0.350 L = 0.14 mol

mass of HCl that makes 0.14 mol of HCl = # of moles x molar mass of HCl

mass of HCl = 0.14 mol x 36.5 g/ mol

mass of HCl = 5.11g

Answer 2

Given - Mass of Ca(OH)2 = 150 gram

Find - Moles of HCl required to fully react

Solution - The chemical reaction between Ca(OH)2 and HCl is as follows -

Ca(OH)2 + 2HCl --> CaCl2 + 2H2O

Ca(OH)2 is Calcium hydroxide, HCl is hydrochloric acid, CaCl2 is calcium chloride and H2O is water.

In the reaction, 1 mole of Ca(OH)2 reacts with 2 moles of HCl.

So, available moles of Ca(OH)2 = 150/75

Moles of Ca(OH)2 = 2

Now, 2 moles of Ca(OH)2 will react with moles of HCl = 2*2

Moles of HCl required for reaction = 4

Hence, 4 moles of HCl are required to react with 150 gram of Ca(OH)2.