when an article is sold for rs 703 loss incurred is 25%less than the profit earned on selling it at rs 836.what is the selling price of the article when it earns a profit of 20%?
Answers
let cp=y
profit when sp=836
x=836-y
loss when sold in 703=3x/4
3x/4=y-703
put the value of x
627-3y/4=y-703
1330=7y/4
y=760
cp when profitis 20%
cp=760+152=912
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Answer:
Let the cost price be x
x
loss incurred when sold at $703 rArr (x - 703)
$
703
⇒
(
x
−
703
)
profit earned when sold at $836 rArr (836 - x)
$
836
⇒
(
836
−
x
)
Therefore;
Since its a loss of 25%
25
%
, (100 - 25)% = 75%
(
100
−
25
)
%
=
75
%
(x - 703) = 75/100(836 - x)
(
x
−
703
)
=
75
100
(
836
−
x
)
(x - 703) = 3/4(836 - x)
(
x
−
703
)
=
3
4
(
836
−
x
)
4(x - 703) = 3(836 - x)
4
(
x
−
703
)
=
3
(
836
−
x
)
4x - 2812 = 2508 - 3x
4
x
−
2812
=
2508
−
3
x
Collecting like terms..
4x + 3x = 2508 + 2812
4
x
+
3
x
=
2508
+
2812
7x = 5320
7
x
=
5320
Divide both sides by 7
7
(7x)/7 = 5320/7
7
x
7
=
5320
7
(cancel7x)/cancel7 = 5320/7
x = 5320/7
x = 760
x = $760
selling price of the article at 20%, (100 + 20)% = 120%
sp = 760 xx 120/100
sp = 91200/100
sp = $912
Hence, the selling price of the article when it earns a profit of 20% is $912