Physics, asked by vicneyaf9257, 1 year ago

When an automobile moving with a speed of 36 km per hour creatures are incline root of 30 degree angle if its coefficient of friction is 0. 1 and the engine is switched off then how much distance will it cover to come at rest 1 g is equal to 10 m per second square?

Answers

Answered by Shaizakincsem
6

P = f + W Sinθ

But, f = μW cos θ = μmg cosθ

Where m = mass of automobile

P = μmgcosθ + mg sinθ

a = p/m = μmgcosθ + mgsinθ/m

= μgcosθ + gsinθ

=(0.1 x 10 x √3/2) + (10 x 1/2)

= 5.866 m/s²

If we consider the law of motion

Distance traveled after when the engine will be switched off

v² = u² - 2as

=> s = u²-v²/2a

= (36x5/18)² - 0/2 x 5.866

= 8.52m

the final velocity v after coming to rest is zero.

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