Question

When an element forms an oxide in which oxygen
is 20% of the oxide by mass, the equivalent mass
of the element will be -
(1) 32 (2) 40 (3) 60 (4) 128​

Answer 1

$\huge\underline\green{\sf Answer:-}</p><p>$

★$\large{\boxed{\sf E_{wt}\:Of\: element=32}}$

$\huge\underline\green{\sf Solution:-}$

★$\large{\boxed{\sf E_{wt}\:of\: element=E_{wt}\:Of\:Oxygen}}$

$\large{\sf {\frac{80}{E}}={\frac{20}{8}}}$

$\large{\sf E ={\frac{80×8}{20}}}$

★$\huge\red{\boxed{\sf E =32}}$

EXTRA INFO. :-

Equivalent weight for diatomic molecules :-

$\large{\sf E_{wt}={\frac{Molecular\: Weight}{2}}}$

Equivalent weight of Monoatomic Molecule :-

$\large{\sf E_{wt}={\frac{Molecular\: Weight}{1}}}$

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