Question

When an ideal diatomic gas is heated at constant pressure, its intenal energy is increased by 50cal then the work done by the gas is

Answer 1

Answer:

internal energy is increased by 50 calories

Answer 2

Answer: Given that,

dU=50cal , Vdiatomic gas =1.4 r= gamma

Explanation:

Q=dU+dW

dU×r =dU+dW (dQ = mCpdT)

dU/dW = 1/r-1

dW= dU ×r-1

=50× (1.4-1)

= 20 cal

The work done by the gas is 20 cal

Hope it helps you