Question

When an ideal gas undergoing isothermal expansion in vacuum shows ∆u=w=q=0. why why why ​

Answer 1

Answer:

Explanation:

We know that in isothermal process temperature is constant, due to which (T2- T1) is zero.

Now,

U=nCvm(T2-T1)=0

q= nCpm(T2-T1)=0

DeltaU= q+w , therefore w=0