Question

When an inductor is connected to a 230 V A.C Source a current of 2 A flows across it. When same inductor is connected to an A.C source of 230V 50Hz the amount of current reduces to 1 A. Why?

Answer 1

It is becausean inductor is connected to a 230 V A.C Source a current of 2 A flows across it. When same inductor is connected to an A.C source of 230V 50Hz the amount of current reduces to 1 A.

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Answer 2

The amount of current reduces to 1 A.

Explanation:

Given that,

Voltage = 230 V

Current = 2 A

Frequency = 50 Hz

When dc source used then an inductor acts resistor.

We need to calculate the resistance

Using ohm's law

$V=IR$

$R=\dfrac{V}{I}$

Put the value into the formula

$R=\dfrac{230}{2}$

$R=115\ \Omega$

The ac current is

$I_{c}=\dfrac{V}{R}$

When ac source used then both R and $\Delta L$ are coincident together which is become impedance.

$z=\sqrty{R^2+X_{L}^2}$

We know that,

$X_{L}=2\pi f$

So, $z > R$

The ac current is

$I_{ac}=\dfrac{V}{z}$

So, $I_{ac}<I_{dc}$

We can say that,

The reduced current is 1 A.

Hence, The amount of current reduces to 1 A.

Learn more :

Topic : impedance

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