Question

When an instrument is at P the staff readings on P is 1.824 and on Q is 2.748. When the instrument at Q the staff readings on P is 0.928 and Q is 1.606. Distance between P and Q is 1010 mts. R.L. of P is 126.386. Find true R.L. of Q?

Answer 1

Answer:

I don't know

brother

sorry

Answer 2

Given:

P = 1.824

Q = 2.748

To Find:

The true R.L. of Q

Explanation:

Therefore true elevation of Q is 126.386 + 0.801 = 127.187 m.

When instrument is at P the staff readings on Q = 2.748 and on P =1.824 when instrument at Q the staff readings on Q = 1.606and P = 0.928.

Distance between P and Q = 1010 mts.

0.069 m

Combined correction for curvature and refraction is 0.06728

d² = 0.06728(1.010)² = 0.069 mts.

Answer = 0.069 mts.