when
an iron rod
of length 56 cm is bent
Into a rectangle. The length of the digonal is
20 cm. Find the length and breadth of the Rectangle.
Answers
Answer:
(a) Perimeter is 56 cm
( l + b )× 2 = perimeter
l + b = Perimeter ÷ 2
l + b= 56÷2=28 cm
Answer is 28 cm
Step-by-step explanation:
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Answer:
Step-by-step explanation:
length of rod=l=56cm
Now we know that
2(l+b)=56
so
l+b=28 ...........(1)
which is (a)
for b
if we take the diagonal as the hypotenuse of a right angled triangle and the length and breadth of the rectangle as the other two sides
l^2+b^2=diagonal^2 ..........(2)
from (1)
l=28-b
Sub in (2)
(28-b)^2 + b^2=diagonal^2
784 - 56b +b^2+b^2=(20)^2
384-56b+2b^2=0
192-28b+b^2=0
D=b^2-4ac=784-768=16
b=(-b(+/-)rootD)/2a=(28(+/-)16)/2=
b=22 or b=6
Now take these values as two case and substitute each of the values in (1) and you will get your answer
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