Question

When an object 5 cm height is placed at a distance 60 cm in front of a concave mirror of focal length 10 cm find the position and size of the image please send the correct step by step explanation​

Answer 1

Answer:

1 Cm

Explanation:

Given,

Size of object h

o

=5cm

Size of the image h

i

=?

Focal length, f=−10cm

Object distance u=−60cm

Image distance v=?

Using mirror formula,

f

1

=

v

1

+

u

1

−10

1

=

v

1

+

−60

1

v

1

=

60

−6+1

v=−12cm

Hence, the position of the object is at 12 cm in front of the mirror.

Magnification (M)=

h

o

h

i

=

u

−v

=

−60

12

=−0.2

h

i

=−0.2×h

o

h

i

=−0.2×5=−1cm

Height of inverted image is 1cm.

Answer 2

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