When an object falls on the ground the earth moves up to meet it. Why is the earth's motion not noticeable?
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The gravitational force existing between any masses M and m( M>>m) is GMm/r² where r is the separation distance.
For the Earth having a mass M
Force= Ma = GMm/r²
So a = Gm/r²
As the value of m for any object is small as compared to that of earth the acceleration of earth towards the object is very small(Again the value of G is small too).
So earth do moves but the change is not noticed.
For the Earth having a mass M
Force= Ma = GMm/r²
So a = Gm/r²
As the value of m for any object is small as compared to that of earth the acceleration of earth towards the object is very small(Again the value of G is small too).
So earth do moves but the change is not noticed.
Rashi2214:
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Answered by
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a=GMm/r^2
So as compared to the earth all the masses will be small or negligible.
Therefore the earth motion is also negligible.
So as compared to the earth all the masses will be small or negligible.
Therefore the earth motion is also negligible.
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