When an object is dropped from height of 100 m from the surface of the earth after 3 sec . What will be distance travelled by the object ?
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given
Height= 100 m
t= 3 seconds
u= 0
g =9.8m/s^2
s= ut+1/2gt^2
s=0*2+1/2*9.8*3*3
=1/2*9.8*3*3
=4.9*9=44.1m
Height= 100 m
t= 3 seconds
u= 0
g =9.8m/s^2
s= ut+1/2gt^2
s=0*2+1/2*9.8*3*3
=1/2*9.8*3*3
=4.9*9=44.1m
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