Question

when an object is kept in front of a spherical lens of radius of curvature 60 cm an erect image of height 1/4th of the height of object is formed. find postion of image and object​

Answer 1

Answer:

Object distance u=−10 cm

Radius of curvature of concave mirror  R=−15 cm

Thus its focal length f=2R=−215 cm

Using mirror formula :  v1+u1=f1

∴ v1+−101=−152

⟹ v=−30 cm

Magnification m=u−v

∴ m=−10−(−30)=−3

Negative sign indicates that the image formed is inverted in nature.

Magnitude of magnification is greater than 1 which indicates that magnified image is formed.

Explanation:

you do your just like that

Answer 2

Explanation:

this is the answer to the question please follow me