When an object is made to float in two different
liquids of densities d1, and d2, the length of the object
seen above the liquid surface are 4 cm and 5 cm
respectively. Which of the following is the correct
alternative?
A. d1>d2
B. d1<d2
C. d1= d2
D. None of these
pls answer only if you are sure
Answers
A
Explanation:
If the density of liquid less then object's it will float or more part will remain outside water . So
d2 < d1
You can do exact calculation by balancing buoyancy and gravition forces .
When an object is made to float in two different liquids of densities d1 and d2, the length of the object seen above the liquid surface are 4 cm and 5 cm respectively.
d1 < d2
Therefore, Option B is correct
Explanation:
We know that the object will float in the liquid if the weight of the liquid displaced by the object is is sufficient enough to balance the weight of the object.
The liquid displaced by the object in the case of liquid with density d1 will be more than that of the liquid displaced in case of liquid of density d2
Therefore, the volume of liquid in case of d1 density is more than that in case of d2 density
Therefore, d1 < d2 as they both are balancing the same weight of the object.
Hope this helps.
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